Kód: Vybrať všetko

Hi! I am Dileep
I have another trick which is used to calculate days of any date of any year…..
A very simple trick for which u have to by-heart just the following series :
1 4 3 6 1 4 6 2 5 0 3 5
steps are as follows:
let the date be the 12th day of the 5th month of 2003
1. find date mod 7. here it is,12 mod 7 ; the no. is 5
2. the month no. is 5; therefore count 5 from the above list of nos., and add that no. to the above no. here the no. is 1 and the sum is 5+1=6;
3. subtract the 1st 2 digits of the year from 19. add the resultant no. to the above got no. here, the no. is 19-20= -1;the sum is 6+-1 = 5
4. find the mod of the rest 2 digits of the year with 7.; add the result to the above no. here the no. is 03 mod 7 = 3; the sum is 5+3=8
5. divide the same 2 digits by 4; mask out the fractions ,if any. find the mod of the resultant no. with 7. here,03 mod 7= (3/4) masking out the fraction, we get 0. 0 nod 7 is 0.therefore the sum is 8+0=8
6. find the mod of the sum with 7. here ,8 mod 7= 1
if the answer is 0 then it is sun
if the answer is 1 then it is mon
if the answer is 2 then it is tue
if the answer is 3 then it is wed
if the answer is 4 then it is thu
if the answer is 5 then it is fri
if the answer is 6 then it is sat